-8v^2+5-9v=2-9v-5v^2

Solution for -8v^2+5-9v=2-9v-5v^2 equation:

-8v^2+5-9v=2-9v-5v^2

We move all terms to the left:

-8v^2+5-9v-(2-9v-5v^2)=0

We get rid of parentheses

-8v^2+5v^2+9v-9v-2+5=0

We add all the numbers together, and all the variables

-3v^2+3=0

a = -3; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-3)·3
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*-3}=\frac{-6}{-6}
=1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*-3}=\frac{6}{-6}
=-1
$